10y-3(2y-5)=6(8-3y)

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Solution for 10y-3(2y-5)=6(8-3y) equation: 



10y-3(2y-5)=6(8-3y)

We move all terms to the left:

10y-3(2y-5)-(6(8-3y))=0

We add all the numbers together, and all the variables

10y-3(2y-5)-(6(-3y+8))=0

We multiply parentheses

10y-6y-(6(-3y+8))+15=0



We calculate terms in parentheses: -(6(-3y+8)), so:

6(-3y+8)

We multiply parentheses

-18y+48

Back to the equation:

-(-18y+48)



We add all the numbers together, and all the variables

4y-(-18y+48)+15=0

We get rid of parentheses

4y+18y-48+15=0

We add all the numbers together, and all the variables

22y-33=0

We move all terms containing y to the left, all other terms to the right

22y=33

y=33/22

y=1+1/2

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