10x2-7x+1=0

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Solution for 10x2-7x+1=0 equation: 



10x^2-7x+1=0

a = 10; b = -7; c = +1;
Δ = b2-4ac
Δ = -72-4·10·1
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$


$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-3}{2*10}=\frac{4}{20}
=1/5
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+3}{2*10}=\frac{10}{20}
=1/2
$

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