-8-2p=3(-10/3p+2)

Solution for -8-2p=3(-10/3p+2) equation:

-8-2p=3(-10/3p+2)

We move all terms to the left:

-8-2p-(3(-10/3p+2))=0


Domain of the equation: 3p+2))!=0

p∈R


We multiply all the terms by the denominator


-2p*3p-8*3p-10+2))-(3(+2))=0

We add all the numbers together, and all the variables

-2p*3p-8*3p-10+2))-(32)=0

We add all the numbers together, and all the variables

-2p*3p-8*3p=0

Wy multiply elements

-6p^2-24p=0

a = -6; b = -24; c = 0;
Δ = b2-4ac
Δ = -242-4·(-6)·0
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-24}{2*-6}=\frac{0}{-12}
=0
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+24}{2*-6}=\frac{48}{-12}
=-4
$