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10x^2+10x+10=9x^2+7x+118
We move all terms to the left:
10x^2+10x+10-(9x^2+7x+118)=0
We get rid of parentheses
10x^2-9x^2+10x-7x-118+10=0
We add all the numbers together, and all the variables
x^2+3x-108=0
a = 1; b = 3; c = -108;
Δ = b2-4ac
Δ = 32-4·1·(-108)
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{441}=21$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-21}{2*1}=\frac{-24}{2} =-12 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+21}{2*1}=\frac{18}{2} =9 $
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