10x-72=(3x-4)2

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Solution for 10x-72=(3x-4)2 equation: 



10x-72=(3x-4)2

We move all terms to the left:

10x-72-((3x-4)2)=0



We calculate terms in parentheses: -((3x-4)2), so:

(3x-4)2

We multiply parentheses

6x-8

Back to the equation:

-(6x-8)



We get rid of parentheses

10x-6x+8-72=0

We add all the numbers together, and all the variables

4x-64=0

We move all terms containing x to the left, all other terms to the right

4x=64

x=64/4

x=16

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