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10x-72=3x-4x^2
We move all terms to the left:
10x-72-(3x-4x^2)=0
We get rid of parentheses
4x^2-3x+10x-72=0
We add all the numbers together, and all the variables
4x^2+7x-72=0
a = 4; b = 7; c = -72;
Δ = b2-4ac
Δ = 72-4·4·(-72)
Δ = 1201
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{1201}}{2*4}=\frac{-7-\sqrt{1201}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{1201}}{2*4}=\frac{-7+\sqrt{1201}}{8} $
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