10x-2(4+x)=4(2x-2)

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Solution for 10x-2(4+x)=4(2x-2) equation: 



10x-2(4+x)=4(2x-2)

We move all terms to the left:

10x-2(4+x)-(4(2x-2))=0

We add all the numbers together, and all the variables

10x-2(x+4)-(4(2x-2))=0

We multiply parentheses

10x-2x-(4(2x-2))-8=0



We calculate terms in parentheses: -(4(2x-2)), so:

4(2x-2)

We multiply parentheses

8x-8

Back to the equation:

-(8x-8)



We add all the numbers together, and all the variables

8x-(8x-8)-8=0

We get rid of parentheses

8x-8x+8-8=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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