-2(2v-2)=2(3-3v)

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Solution for -2(2v-2)=2(3-3v) equation: 



-2(2v-2)=2(3-3v)

We move all terms to the left:

-2(2v-2)-(2(3-3v))=0

We add all the numbers together, and all the variables

-2(2v-2)-(2(-3v+3))=0

We multiply parentheses

-4v-(2(-3v+3))+4=0



We calculate terms in parentheses: -(2(-3v+3)), so:

2(-3v+3)

We multiply parentheses

-6v+6

Back to the equation:

-(-6v+6)



We get rid of parentheses

-4v+6v-6+4=0

We add all the numbers together, and all the variables

2v-2=0

We move all terms containing v to the left, all other terms to the right

2v=2

v=2/2

v=1

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