10x-19=(3x+2)+(5x-3)

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Solution for 10x-19=(3x+2)+(5x-3) equation: 



10x-19=(3x+2)+(5x-3)

We move all terms to the left:

10x-19-((3x+2)+(5x-3))=0



We calculate terms in parentheses: -((3x+2)+(5x-3)), so:

(3x+2)+(5x-3)

We get rid of parentheses

3x+5x+2-3

We add all the numbers together, and all the variables

8x-1

Back to the equation:

-(8x-1)



We get rid of parentheses

10x-8x+1-19=0

We add all the numbers together, and all the variables

2x-18=0

We move all terms containing x to the left, all other terms to the right

2x=18

x=18/2

x=9

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