10x+8-2(3x-4)=-12

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Solution for 10x+8-2(3x-4)=-12 equation: 



10x+8-2(3x-4)=-12

We move all terms to the left:

10x+8-2(3x-4)-(-12)=0

We add all the numbers together, and all the variables

10x-2(3x-4)+20=0

We multiply parentheses

10x-6x+8+20=0

We add all the numbers together, and all the variables

4x+28=0

We move all terms containing x to the left, all other terms to the right

4x=-28

x=-28/4

x=-7

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