10x+6-4-3x=5(x-4)-3(x-4)

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Solution for 10x+6-4-3x=5(x-4)-3(x-4) equation: 



10x+6-4-3x=5(x-4)-3(x-4)

We move all terms to the left:

10x+6-4-3x-(5(x-4)-3(x-4))=0

We add all the numbers together, and all the variables

7x-(5(x-4)-3(x-4))+2=0



We calculate terms in parentheses: -(5(x-4)-3(x-4)), so:

5(x-4)-3(x-4)

We multiply parentheses

5x-3x-20+12

We add all the numbers together, and all the variables

2x-8

Back to the equation:

-(2x-8)



We get rid of parentheses

7x-2x+8+2=0

We add all the numbers together, and all the variables

5x+10=0

We move all terms containing x to the left, all other terms to the right

5x=-10

x=-10/5

x=-2

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