-n=(3n-3)/2-n-1

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Solution for -n=(3n-3)/2-n-1 equation: 



-n=(3n-3)/2-n-1

We move all terms to the left:

-n-((3n-3)/2-n-1)=0



Domain of the equation: 2-n-1)!=0

We move all terms containing n to the left, all other terms to the right

-n-1)!=-2

n∈R



We add all the numbers together, and all the variables

-1n-((3n-3)/2-n-1)=0

We multiply all the terms by the denominator


-1n*2-n-1)-((3n-3)=0

We add all the numbers together, and all the variables

-1n-1n*2-1)-((3n-3)=0

Wy multiply elements

-1n-2n-1)-((3n-3)=0

We add all the numbers together, and all the variables

-3n-1)-((3n-3)=0

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