2k-12=7(1+3k)

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Solution for 2k-12=7(1+3k) equation: 



2k-12=7(1+3k)

We move all terms to the left:

2k-12-(7(1+3k))=0

We add all the numbers together, and all the variables

2k-(7(3k+1))-12=0



We calculate terms in parentheses: -(7(3k+1)), so:

7(3k+1)

We multiply parentheses

21k+7

Back to the equation:

-(21k+7)



We get rid of parentheses

2k-21k-7-12=0

We add all the numbers together, and all the variables

-19k-19=0

We move all terms containing k to the left, all other terms to the right

-19k=19

k=19/-19

k=-1

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