10x+4x=5(x-6)+33

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Solution for 10x+4x=5(x-6)+33 equation:



10x+4x=5(x-6)+33
We move all terms to the left:
10x+4x-(5(x-6)+33)=0
We add all the numbers together, and all the variables
14x-(5(x-6)+33)=0
We calculate terms in parentheses: -(5(x-6)+33), so:
5(x-6)+33
We multiply parentheses
5x-30+33
We add all the numbers together, and all the variables
5x+3
Back to the equation:
-(5x+3)
We get rid of parentheses
14x-5x-3=0
We add all the numbers together, and all the variables
9x-3=0
We move all terms containing x to the left, all other terms to the right
9x=3
x=3/9
x=1/3

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