If it's not what You are looking for type in the equation solver your own equation and let us solve it.
10x+4=2(8x-23)
We move all terms to the left:
10x+4-(2(8x-23))=0
We calculate terms in parentheses: -(2(8x-23)), so:We get rid of parentheses
2(8x-23)
We multiply parentheses
16x-46
Back to the equation:
-(16x-46)
10x-16x+46+4=0
We add all the numbers together, and all the variables
-6x+50=0
We move all terms containing x to the left, all other terms to the right
-6x=-50
x=-50/-6
x=8+1/3
| 10y+5=12-15y | | -16=2+3w | | f–354=1,221 | | -3m-(5-2m)=-10 | | -3(8x);x=1,4= | | 10+13x(2-4)=24 | | 181=102-w | | 2(x-3)-18=6-4x | | 4x-3=75 | | 5m-13=59 | | 1/8k-6=3/8k+4 | | b/6+62=71 | | -10=x-27 | | 4k-12=37 | | 64x+62x-2=180 | | (6c-4)-(c-3;c=-7= | | 3c-68=51 | | 73=3g-17 | | 80=4(n+6) | | j+28/10=7 | | 2(x+4)-10x=3(x+6) | | 2X22=7x-3 | | 89=4c+21 | | 5x-9=2(11x-3) | | 77x+1+78x=180 | | p/7+27=32 | | (2b+1)-b;b=-4= | | t/2+9=11 | | 6p^2-p=1 | | x=36-15 | | 37x+1+53x-1=180 | | 7*10^(-9)=(x(3x)^(3)))/(6-2x)^(2) |