j+28/10=7

Simple and best practice solution for j+28/10=7 equation. Check how easy it is, and learn it for the future. Our solution is simple, and easy to understand, so don`t hesitate to use it as a solution of your homework.

If it's not what You are looking for type in the equation solver your own equation and let us solve it.

Solution for j+28/10=7 equation: 



j+28/10=7

We move all terms to the left:

j+28/10-(7)=0

determiningTheFunctionDomain
j-7+28/10=0

We multiply all the terms by the denominator


j*10+28-7*10=0

We add all the numbers together, and all the variables

j*10-42=0

Wy multiply elements

10j-42=0

We move all terms containing j to the left, all other terms to the right

10j=42

j=42/10

j=4+1/5

See similar equations:

| 2(x+4)-10x=3(x+6) | | 2X22=7x-3 | | 89=4c+21 | | 5x-9=2(11x-3) | | 77x+1+78x=180 | | p/7+27=32 | | (2b+1)-b;b=-4= | | t/2+9=11 | | 6p^2-p=1 | | x=36-15 | | 37x+1+53x-1=180 | | 7*10^(-9)=(x(3x)^(3)))/(6-2x)^(2) | | 15x+2=-3x+11 | | 99=3p-63 | | 7*10^-9=(x(3x)^(3)))/(6-2x)^(2) | | 7*10^-9=(x(3x)^3))/(6-2x)^2 | | 4y-(3+y);y=2= | | -3+11(7)=x | | -3+11x+16x-6=180 | | 1/2b+1/3b-20=10 | | q/6+39=44 | | 8x-18=2(2x+5) | | (2^(3x))(2^(5x))=16 | | 1/46+x=6 | | 5x^2+20x-300=0 | | 1/4+6+x=6 | | b-79/7=2 | | 10=s/3+9 | | 16x+21x-5=180 | | r+19/8=5 | | y-3/8=10 | | 2+1/2x+3/8x=16 |

Equations solver categories