10x+(8-x)=5(8-x)-4

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Solution for 10x+(8-x)=5(8-x)-4 equation: 



10x+(8-x)=5(8-x)-4

We move all terms to the left:

10x+(8-x)-(5(8-x)-4)=0

We add all the numbers together, and all the variables

10x+(-1x+8)-(5(-1x+8)-4)=0

We get rid of parentheses

10x-1x-(5(-1x+8)-4)+8=0



We calculate terms in parentheses: -(5(-1x+8)-4), so:

5(-1x+8)-4

We multiply parentheses

-5x+40-4

We add all the numbers together, and all the variables

-5x+36

Back to the equation:

-(-5x+36)



We add all the numbers together, and all the variables

9x-(-5x+36)+8=0

We get rid of parentheses

9x+5x-36+8=0

We add all the numbers together, and all the variables

14x-28=0

We move all terms containing x to the left, all other terms to the right

14x=28

x=28/14

x=2

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