10x+(11-x)-45=10(11-x)+x

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Solution for 10x+(11-x)-45=10(11-x)+x equation: 



10x+(11-x)-45=10(11-x)+x

We move all terms to the left:

10x+(11-x)-45-(10(11-x)+x)=0

We add all the numbers together, and all the variables

10x+(-1x+11)-(10(-1x+11)+x)-45=0

We get rid of parentheses

10x-1x-(10(-1x+11)+x)+11-45=0



We calculate terms in parentheses: -(10(-1x+11)+x), so:

10(-1x+11)+x

We add all the numbers together, and all the variables

x+10(-1x+11)

We multiply parentheses

x-10x+110

We add all the numbers together, and all the variables

-9x+110

Back to the equation:

-(-9x+110)



We add all the numbers together, and all the variables

9x-(-9x+110)-34=0

We get rid of parentheses

9x+9x-110-34=0

We add all the numbers together, and all the variables

18x-144=0

We move all terms containing x to the left, all other terms to the right

18x=144

x=144/18

x=8

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