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10x(3x-6)=9
We move all terms to the left:
10x(3x-6)-(9)=0
We multiply parentheses
30x^2-60x-9=0
a = 30; b = -60; c = -9;
Δ = b2-4ac
Δ = -602-4·30·(-9)
Δ = 4680
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4680}=\sqrt{36*130}=\sqrt{36}*\sqrt{130}=6\sqrt{130}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-6\sqrt{130}}{2*30}=\frac{60-6\sqrt{130}}{60} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+6\sqrt{130}}{2*30}=\frac{60+6\sqrt{130}}{60} $
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