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7/2x+1/2=3+5/2x
We move all terms to the left:
7/2x+1/2-(3+5/2x)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: 2x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
7/2x-(5/2x+3)+1/2=0
We get rid of parentheses
7/2x-5/2x-3+1/2=0
We calculate fractions
-3!=0
There is no solution for this equation
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