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10t=3/4(t)
We move all terms to the left:
10t-(3/4(t))=0
Domain of the equation: 4t)!=0We add all the numbers together, and all the variables
t!=0/1
t!=0
t∈R
10t-(+3/4t)=0
We get rid of parentheses
10t-3/4t=0
We multiply all the terms by the denominator
10t*4t-3=0
Wy multiply elements
40t^2-3=0
a = 40; b = 0; c = -3;
Δ = b2-4ac
Δ = 02-4·40·(-3)
Δ = 480
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{480}=\sqrt{16*30}=\sqrt{16}*\sqrt{30}=4\sqrt{30}$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{30}}{2*40}=\frac{0-4\sqrt{30}}{80} =-\frac{4\sqrt{30}}{80} =-\frac{\sqrt{30}}{20} $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{30}}{2*40}=\frac{0+4\sqrt{30}}{80} =\frac{4\sqrt{30}}{80} =\frac{\sqrt{30}}{20} $
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