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x(8x+2)=300
We move all terms to the left:
x(8x+2)-(300)=0
We multiply parentheses
8x^2+2x-300=0
a = 8; b = 2; c = -300;
Δ = b2-4ac
Δ = 22-4·8·(-300)
Δ = 9604
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9604}=98$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-98}{2*8}=\frac{-100}{16} =-6+1/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+98}{2*8}=\frac{96}{16} =6 $
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