If it's not what You are looking for type in the equation solver your own equation and let us solve it.
10r^2+10r-60=0
a = 10; b = 10; c = -60;
Δ = b2-4ac
Δ = 102-4·10·(-60)
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2500}=50$$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-50}{2*10}=\frac{-60}{20} =-3 $$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+50}{2*10}=\frac{40}{20} =2 $
| 3x-4=52-x | | (x1−3)(x2+5)−(x2−3)(x1+5)=0 | | 9x-30+6x=4+14-x | | 9x+15=49-7x | | -14+x2=11 | | a7=10 | | 16+6m=106 | | Y=-16x+5 | | 17-7x2=3 | | t^2+9t=10 | | 5m(m-3)=4(m-6) | | 8^(2x-1)=16x | | x/2-7=x/3 | | 2(h-1)=2 | | 5k-2=-8k+3+11k | | (2x–4)(–x+6)=0 | | 3z+914z=4z+5 | | 7x^2-2=54 | | 7x+8x=12+–12 | | 11w−w=10 | | 4x²-8x+21=0 | | 8(y+3)=5y | | 8(10-k7=2k | | 7(-2)-8(4-3x)=47 | | 13v−10v=15 | | 4x2–2x–3=0 | | 3(s+4)=s–6 | | 4x-5=-25+6x | | 6n–7=3n+7 | | 3) 5t+3=2t+15 | | 4x+7=38-5x | | 106=17+6m |