5m(m-3)=4(m-6)

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Solution for 5m(m-3)=4(m-6) equation: 



5m(m-3)=4(m-6)

We move all terms to the left:

5m(m-3)-(4(m-6))=0

We multiply parentheses

5m^2-15m-(4(m-6))=0



We calculate terms in parentheses: -(4(m-6)), so:

4(m-6)

We multiply parentheses

4m-24

Back to the equation:

-(4m-24)



We get rid of parentheses

5m^2-15m-4m+24=0

We add all the numbers together, and all the variables

5m^2-19m+24=0

a = 5; b = -19; c = +24;
Δ = b2-4ac
Δ = -192-4·5·24
Δ = -119
Delta is less than zero, so there is no solution for the equation

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