10n+5(10n-2)=2(25n+20)

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Solution for 10n+5(10n-2)=2(25n+20) equation: 



10n+5(10n-2)=2(25n+20)

We move all terms to the left:

10n+5(10n-2)-(2(25n+20))=0

We multiply parentheses

10n+50n-(2(25n+20))-10=0



We calculate terms in parentheses: -(2(25n+20)), so:

2(25n+20)

We multiply parentheses

50n+40

Back to the equation:

-(50n+40)



We add all the numbers together, and all the variables

60n-(50n+40)-10=0

We get rid of parentheses

60n-50n-40-10=0

We add all the numbers together, and all the variables

10n-50=0

We move all terms containing n to the left, all other terms to the right

10n=50

n=50/10

n=5

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