10h(6h+7)=0

Solution for 10h(6h+7)=0 equation:

10h(6h+7)=0

We multiply parentheses

60h^2+70h=0

a = 60; b = 70; c = 0;
Δ = b2-4ac
Δ = 702-4·60·0
Δ = 4900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4900}=70$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(70)-70}{2*60}=\frac{-140}{120}
=-1+1/6
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(70)+70}{2*60}=\frac{0}{120}
=0
$