1/4(4x+12)-3(x-4)=13

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Solution for 1/4(4x+12)-3(x-4)=13 equation: 



1/4(4x+12)-3(x-4)=13

We move all terms to the left:

1/4(4x+12)-3(x-4)-(13)=0



Domain of the equation: 4(4x+12)!=0

x∈R



We multiply parentheses

1/4(4x+12)-3x+12-13=0

We multiply all the terms by the denominator


-3x*4(4x+12)+12*4(4x+12)-13*4(4x+12)+1=0

Wy multiply elements

-12x^2(4+48x(4-52x(4+1=0

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