10g(-4-2g)=-4-20g

Solution for 10g(-4-2g)=-4-20g equation:

10g(-4-2g)=-4-20g

We move all terms to the left:

10g(-4-2g)-(-4-20g)=0

We add all the numbers together, and all the variables

10g(-2g-4)-(-20g-4)=0

We multiply parentheses

-20g^2-40g-(-20g-4)=0

We get rid of parentheses

-20g^2-40g+20g+4=0

We add all the numbers together, and all the variables

-20g^2-20g+4=0

a = -20; b = -20; c = +4;
Δ = b2-4ac
Δ = -202-4·(-20)·4
Δ = 720
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{720}=\sqrt{144*5}=\sqrt{144}*\sqrt{5}=12\sqrt{5}$
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-12\sqrt{5}}{2*-20}=\frac{20-12\sqrt{5}}{-40}
$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+12\sqrt{5}}{2*-20}=\frac{20+12\sqrt{5}}{-40}
$