4z+9+3(2z)=119

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Solution for 4z+9+3(2z)=119 equation: 



4z+9+3(2z)=119

We move all terms to the left:

4z+9+3(2z)-(119)=0

We add all the numbers together, and all the variables

36z-110=0

We move all terms containing z to the left, all other terms to the right

36z=110

z=110/36

z=3+1/18

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