10f+2(2f-9)=6f-(8f-10)

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Solution for 10f+2(2f-9)=6f-(8f-10) equation: 



10f+2(2f-9)=6f-(8f-10)

We move all terms to the left:

10f+2(2f-9)-(6f-(8f-10))=0

We multiply parentheses

10f+4f-(6f-(8f-10))-18=0



We calculate terms in parentheses: -(6f-(8f-10)), so:

6f-(8f-10)

We get rid of parentheses

6f-8f+10

We add all the numbers together, and all the variables

-2f+10

Back to the equation:

-(-2f+10)



We add all the numbers together, and all the variables

14f-(-2f+10)-18=0

We get rid of parentheses

14f+2f-10-18=0

We add all the numbers together, and all the variables

16f-28=0

We move all terms containing f to the left, all other terms to the right

16f=28

f=28/16

f=1+3/4

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