2(6v-7)=3(4v+2)

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Solution for 2(6v-7)=3(4v+2) equation: 



2(6v-7)=3(4v+2)

We move all terms to the left:

2(6v-7)-(3(4v+2))=0

We multiply parentheses

12v-(3(4v+2))-14=0



We calculate terms in parentheses: -(3(4v+2)), so:

3(4v+2)

We multiply parentheses

12v+6

Back to the equation:

-(12v+6)



We get rid of parentheses

12v-12v-6-14=0

We add all the numbers together, and all the variables

-20!=0

There is no solution for this equation

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