10d+3d+5=2(d-3)+5=2(d-3)*

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Solution for 10d+3d+5=2(d-3)+5=2(d-3)* equation: 



10d+3d+5=2(d-3)+5=2(d-3)*

We move all terms to the left:

10d+3d+5-(2(d-3)+5)=0

We add all the numbers together, and all the variables

13d-(2(d-3)+5)+5=0



We calculate terms in parentheses: -(2(d-3)+5), so:

2(d-3)+5

We multiply parentheses

2d-6+5

We add all the numbers together, and all the variables

2d-1

Back to the equation:

-(2d-1)



We get rid of parentheses

13d-2d+1+5=0

We add all the numbers together, and all the variables

11d+6=0

We move all terms containing d to the left, all other terms to the right

11d=-6

d=-6/11

d=-6/11

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