+3(+1m+4)=+6(+1m-9)

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Solution for +3(+1m+4)=+6(+1m-9) equation:



+3(+1m+4)=+6(+1m-9)
We move all terms to the left:
+3(+1m+4)-(+6(+1m-9))=0
We add all the numbers together, and all the variables
3(m+4)-(+6(m-9))=0
We multiply parentheses
3m-(+6(m-9))+12=0
We calculate terms in parentheses: -(+6(m-9)), so:
+6(m-9)
determiningTheFunctionDomain 6(m-9)
We multiply parentheses
6m-54
Back to the equation:
-(6m-54)
We get rid of parentheses
3m-6m+54+12=0
We add all the numbers together, and all the variables
-3m+66=0
We move all terms containing m to the left, all other terms to the right
-3m=-66
m=-66/-3
m=+22

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