500=3(x-50)+x-50+x

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Solution for 500=3(x-50)+x-50+x equation:



500=3(x-50)+x-50+x
We move all terms to the left:
500-(3(x-50)+x-50+x)=0
We calculate terms in parentheses: -(3(x-50)+x-50+x), so:
3(x-50)+x-50+x
determiningTheFunctionDomain 3(x-50)+x+x-50
We add all the numbers together, and all the variables
2x+3(x-50)-50
We multiply parentheses
2x+3x-150-50
We add all the numbers together, and all the variables
5x-200
Back to the equation:
-(5x-200)
We get rid of parentheses
-5x+200+500=0
We add all the numbers together, and all the variables
-5x+700=0
We move all terms containing x to the left, all other terms to the right
-5x=-700
x=-700/-5
x=+140

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