10b-45=3(b-3)

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Solution for 10b-45=3(b-3) equation: 



10b-45=3(b-3)

We move all terms to the left:

10b-45-(3(b-3))=0



We calculate terms in parentheses: -(3(b-3)), so:

3(b-3)

We multiply parentheses

3b-9

Back to the equation:

-(3b-9)



We get rid of parentheses

10b-3b+9-45=0

We add all the numbers together, and all the variables

7b-36=0

We move all terms containing b to the left, all other terms to the right

7b=36

b=36/7

b=5+1/7

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