10=6(1-5p)+2(p+2)

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Solution for 10=6(1-5p)+2(p+2) equation: 



10=6(1-5p)+2(p+2)

We move all terms to the left:

10-(6(1-5p)+2(p+2))=0

We add all the numbers together, and all the variables

-(6(-5p+1)+2(p+2))+10=0



We calculate terms in parentheses: -(6(-5p+1)+2(p+2)), so:

6(-5p+1)+2(p+2)

We multiply parentheses

-30p+2p+6+4

We add all the numbers together, and all the variables

-28p+10

Back to the equation:

-(-28p+10)



We get rid of parentheses

28p-10+10=0

We add all the numbers together, and all the variables

28p=0

p=0/28

p=0

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