10=5(t-2)

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Solution for 10=5(t-2) equation: 



10=5(t-2)

We move all terms to the left:

10-(5(t-2))=0



We calculate terms in parentheses: -(5(t-2)), so:

5(t-2)

We multiply parentheses

5t-10

Back to the equation:

-(5t-10)



We get rid of parentheses

-5t+10+10=0

We add all the numbers together, and all the variables

-5t+20=0

We move all terms containing t to the left, all other terms to the right

-5t=-20

t=-20/-5

t=+4

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