(y+1)=10-2(3y-y)

Solution for (y+1)=10-2(3y-y) equation:

(y+1)=10-2(3y-y)

We move all terms to the left:

(y+1)-(10-2(3y-y))=0

We add all the numbers together, and all the variables

(y+1)-(10-2(+2y))=0

We get rid of parentheses

y-(10-2(+2y))+1=0


We calculate terms in parentheses: -(10-2(+2y)), so:

10-2(+2y)

determiningTheFunctionDomain
-2(+2y)+10

We multiply parentheses

-4y+10

Back to the equation:

-(-4y+10)


We get rid of parentheses

y+4y-10+1=0

We add all the numbers together, and all the variables

5y-9=0

We move all terms containing y to the left, all other terms to the right

5y=9

y=9/5

y=1+4/5