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10=3/2(2x+4)
We move all terms to the left:
10-(3/2(2x+4))=0
Domain of the equation: 2(2x+4))!=0We multiply all the terms by the denominator
x∈R
-(3+10*2(2x+4))=0
We calculate terms in parentheses: -(3+10*2(2x+4)), so:We add all the numbers together, and all the variables
3+10*2(2x+4)
determiningTheFunctionDomain 10*2(2x+4)+3
Wy multiply elements
20x(2+3
Back to the equation:
-(20x(2+3)
-(20x5=0
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