-(n-6)=3(n+3)+5

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Solution for -(n-6)=3(n+3)+5 equation: 



-(n-6)=3(n+3)+5

We move all terms to the left:

-(n-6)-(3(n+3)+5)=0

We get rid of parentheses

-n-(3(n+3)+5)+6=0



We calculate terms in parentheses: -(3(n+3)+5), so:

3(n+3)+5

We multiply parentheses

3n+9+5

We add all the numbers together, and all the variables

3n+14

Back to the equation:

-(3n+14)



We add all the numbers together, and all the variables

-1n-(3n+14)+6=0

We get rid of parentheses

-1n-3n-14+6=0

We add all the numbers together, and all the variables

-4n-8=0

We move all terms containing n to the left, all other terms to the right

-4n=8

n=8/-4

n=-2

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