10=2c+4c-38

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Solution for 10=2c+4c-38 equation: 



10=2c+4c-38

We move all terms to the left:

10-(2c+4c-38)=0

We add all the numbers together, and all the variables

-(6c-38)+10=0

We get rid of parentheses

-6c+38+10=0

We add all the numbers together, and all the variables

-6c+48=0

We move all terms containing c to the left, all other terms to the right

-6c=-48

c=-48/-6

c=+8

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