4(3i-2)=81-5

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Solution for 4(3i-2)=81-5 equation: 



4(3i-2)=81-5

We move all terms to the left:

4(3i-2)-(81-5)=0

We add all the numbers together, and all the variables

4(3i-2)-76=0

We multiply parentheses

12i-8-76=0

We add all the numbers together, and all the variables

12i-84=0

We move all terms containing i to the left, all other terms to the right

12i=84

i=84/12

i=7

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