10=2(n-4)+2

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Solution for 10=2(n-4)+2 equation: 



10=2(n-4)+2

We move all terms to the left:

10-(2(n-4)+2)=0



We calculate terms in parentheses: -(2(n-4)+2), so:

2(n-4)+2

We multiply parentheses

2n-8+2

We add all the numbers together, and all the variables

2n-6

Back to the equation:

-(2n-6)



We get rid of parentheses

-2n+6+10=0

We add all the numbers together, and all the variables

-2n+16=0

We move all terms containing n to the left, all other terms to the right

-2n=-16

n=-16/-2

n=+8

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