(4y/7)-(7/8)=(1/56)

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Solution for (4y/7)-(7/8)=(1/56) equation: 



(4y/7)-(7/8)=(1/56)

We move all terms to the left:

(4y/7)-(7/8)-((1/56))=0

We add all the numbers together, and all the variables

(+4y/7)-(+7/8)-((+1/56))=0

We get rid of parentheses

4y/7-7/8-((+1/56))=0

We calculate fractions


8960y^2/()+()/()+()/()=0

We add all the numbers together, and all the variables

8960y^2/()+2=0

We multiply all the terms by the denominator


8960y^2+2*()=0

We add all the numbers together, and all the variables

8960y^2=0

a = 8960; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·8960·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{0}{17920}=0$

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