10=2(c+2)+2

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Solution for 10=2(c+2)+2 equation: 



10=2(c+2)+2

We move all terms to the left:

10-(2(c+2)+2)=0



We calculate terms in parentheses: -(2(c+2)+2), so:

2(c+2)+2

We multiply parentheses

2c+4+2

We add all the numbers together, and all the variables

2c+6

Back to the equation:

-(2c+6)



We get rid of parentheses

-2c-6+10=0

We add all the numbers together, and all the variables

-2c+4=0

We move all terms containing c to the left, all other terms to the right

-2c=-4

c=-4/-2

c=+2

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