6=3(j-7)

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Solution for 6=3(j-7) equation: 



6=3(j-7)

We move all terms to the left:

6-(3(j-7))=0



We calculate terms in parentheses: -(3(j-7)), so:

3(j-7)

We multiply parentheses

3j-21

Back to the equation:

-(3j-21)



We get rid of parentheses

-3j+21+6=0

We add all the numbers together, and all the variables

-3j+27=0

We move all terms containing j to the left, all other terms to the right

-3j=-27

j=-27/-3

j=+9

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