10=10(x-4)+4x-20

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Solution for 10=10(x-4)+4x-20 equation: 



10=10(x-4)+4x-20

We move all terms to the left:

10-(10(x-4)+4x-20)=0



We calculate terms in parentheses: -(10(x-4)+4x-20), so:

10(x-4)+4x-20

We add all the numbers together, and all the variables

4x+10(x-4)-20

We multiply parentheses

4x+10x-40-20

We add all the numbers together, and all the variables

14x-60

Back to the equation:

-(14x-60)



We get rid of parentheses

-14x+60+10=0

We add all the numbers together, and all the variables

-14x+70=0

We move all terms containing x to the left, all other terms to the right

-14x=-70

x=-70/-14

x=+5

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