10=-(1/2)*(1)+b

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Solution for 10=-(1/2)*(1)+b equation: 



10=-(1/2)(1)+b

We move all terms to the left:

10-(-(1/2)(1)+b)=0



Domain of the equation: 2)1+b)!=0

b!=0/1

b!=0

b∈R



We add all the numbers together, and all the variables

-(-(+1/2)1+b)+10=0

We multiply all the terms by the denominator


-(-(+1+10*2)1+b)=0



We calculate terms in parentheses: -(-(+1+10*2)1+b), so:

-(+1+10*2)1+b

determiningTheFunctionDomain
b-(+1+10*2)1

We add all the numbers together, and all the variables

b-211

Back to the equation:

-(b-211)



We get rid of parentheses

-b+211=0

We add all the numbers together, and all the variables

-1b+211=0

We move all terms containing b to the left, all other terms to the right

-b=-211

b=-211/-1

b=+211

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