(x/7)+(x/8)=(9/7)

Solution for (x/7)+(x/8)=(9/7) equation:

(x/7)+(x/8)=(9/7)

We move all terms to the left:

(x/7)+(x/8)-((9/7))=0

We add all the numbers together, and all the variables

(+x/7)+(+x/8)-((+9/7))=0

We get rid of parentheses

x/7+x/8-((+9/7))=0

We calculate fractions


343x^2/()+8x/()+()/()=0

We add all the numbers together, and all the variables

343x^2/()+8x/()+1=0

We multiply all the terms by the denominator


343x^2+8x+1*()=0

We add all the numbers together, and all the variables

343x^2+8x=0

a = 343; b = 8; c = 0;
Δ = b2-4ac
Δ = 82-4·343·0
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-8}{2*343}=\frac{-16}{686}
=-8/343
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+8}{2*343}=\frac{0}{686}
=0
$