10=(3x-1)/2

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Solution for 10=(3x-1)/2 equation: 



10=(3x-1)/2

We move all terms to the left:

10-((3x-1)/2)=0

We multiply all the terms by the denominator


-((3x-1)+10*2)=0



We calculate terms in parentheses: -((3x-1)+10*2), so:

(3x-1)+10*2

We add all the numbers together, and all the variables

(3x-1)+20

We get rid of parentheses

3x-1+20

We add all the numbers together, and all the variables

3x+19

Back to the equation:

-(3x+19)



We get rid of parentheses

-3x-19=0

We move all terms containing x to the left, all other terms to the right

-3x=19

x=19/-3

x=-6+1/3

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